Question

6．一列有規(guī)律的數(shù)：$\sqrt{2}$，2，$\sqrt{6}$，$2\sqrt{2}$，$\sqrt{10}$，…，則第6個(gè)數(shù)是2$\sqrt{3}$，第n個(gè)數(shù)是$\sqrt{2n}$（n為正整數(shù)）．

Answer 1

分析 根據(jù)題意得出規(guī)律第n個(gè)數(shù)是$\sqrt{2n}$解答即可．

解答 解：$\sqrt{2}$，$\sqrt{4}$=2，$\sqrt{6}$，$\sqrt{8}$=$2\sqrt{2}$，$\sqrt{10}$，…，則第6個(gè)數(shù)是$\sqrt{12}$=2$\sqrt{3}$，第n個(gè)數(shù)是$\sqrt{2n}$，
故答案為：2$\sqrt{3}$；$\sqrt{2n}$

點(diǎn)評(píng) 本題主要考查算術(shù)平方根的知識(shí)點(diǎn)，關(guān)鍵是根據(jù)題意得出規(guī)律進(jìn)行解答．