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        1. 計(jì)算:
          (1)
          x2
          x-1
          -x-1

          (2)
          x2+2x
          x2-4
          -
          2
          x-2

          (3)(
          x
          x+1
          -
          3x
          x-1
          )÷
          x
          x2-1

          (4)(1+
          2b
          a-b
          )
          2
          (1
          2b
          a+b
          )
          2
          分析:(1)先通分,再化成最簡(jiǎn)分式即可;
          (2)先通分,再根據(jù)同分母分式的加減法則進(jìn)行計(jì)算,最后化成最簡(jiǎn)分式即可;
          (3)先算括號(hào)里面的,把除法變成乘法,再約分即可;
          (4)先算括號(hào)里面的,再約分即可.
          解答:解:(1)原式=
          x2
          x-1
          -
          x+1
          1

          =
          x2-(x+1)(x-1)
          x-1

          =
          1
          x-1


          (2)原式=
          x(x+2)
          (x+2)(x-2)
          -
          2
          x-2

          =
          x
          x-2
          -
          2
          x-2

          =
          x-2
          x-2

          =1.

          (3)原式=
          x(x-1)-3x(x+1)
          (x+1)(x-1)
          (x+1)(x-1)
          x

          =
          -2x2-4x
          x

          =-2x-4.

          (4)原式=(
          a-b+2b
          a-b
          2•(
          a+3b
          a+b
          2
          =
          (a+b)2
          (a-b)2
          (a+3b)2
          (a+b)2

          =
          (a+3b)2
          (a-b)2

          =
          a2+6ab+9b2
          a2-2ab+b2
          點(diǎn)評(píng):本題考查了分式的混合運(yùn)算的應(yīng)用,主要考查學(xué)生的化簡(jiǎn)和計(jì)算能力.
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