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        1. 乙題: 解:(1)因?yàn)榉幢壤瘮?shù)的圖象經(jīng)過(guò)點(diǎn) 有.················································································································ 2分 .····················································································································· 3分 所以反比例函數(shù)的解析式為.············································································· 4分 (2)當(dāng)為一.三象限角平分線與反比例函數(shù)圖像的交點(diǎn)時(shí). 線段最短.············································································································ 5分 將代入.解得.即..····················· 6分 .··········································································································· 7分 則.··········································································································· 8分 又為反比例函數(shù)圖像上的任意兩點(diǎn). 由圖象特點(diǎn)知.線段無(wú)最大值.即.·················································· 9分 查看更多

           

          題目列表(包括答案和解析)

          甲題:已知x1、x2是關(guān)于x的一元二次方程x2-2x+a-1=0的兩個(gè)實(shí)數(shù)根
          (1)若x1+2x2=3-
          2
          ,求x1、x2及a的值;
          (2)若s=ax1x2+3x1+3x2-3a,求s的取值范圍.
          乙題:如圖,在Rt△ABC中,∠C=90°,AC:AB=
          3
          :2

          (1)求BC:AC的值;
          (2)延長(zhǎng)CB到點(diǎn)D,使DB:DC=2:3,連接AD.
          ①求∠D的度數(shù);②若AD=12,求△ABC三邊的長(zhǎng).
          解:我選做
          題.

          查看答案和解析>>

          (2013•溫州)某校舉辦八年級(jí)學(xué)生數(shù)學(xué)素養(yǎng)大賽,比賽共設(shè)四個(gè)項(xiàng)目:七巧板拼圖,趣題巧解,數(shù)學(xué)應(yīng)用,魔方復(fù)原,每個(gè)項(xiàng)目得分都按一定百分比折算后記入總分,下表為甲,乙,丙三位同學(xué)得分情況(單位:分)
             七巧板拼圖  趣題巧解  數(shù)學(xué)應(yīng)用  魔方復(fù)原
           甲  66  89  86  68
           乙  66  60  80  68
           丙  66  80  90  68
          (1)比賽后,甲猜測(cè)七巧板拼圖,趣題巧解,數(shù)學(xué)應(yīng)用,魔方復(fù)原這四個(gè)項(xiàng)目得分分別按10%,40%,20%,30%折算△記入總分,根據(jù)猜測(cè),求出甲的總分;
          (2)本次大賽組委會(huì)最后決定,總分為80分以上(包含80分)的學(xué)生獲一等獎(jiǎng),現(xiàn)獲悉乙,丙的總分分別是70分,80分.甲的七巧板拼圖、魔方復(fù)原兩項(xiàng)得分折算后的分?jǐn)?shù)和是20分,問(wèn)甲能否獲得這次比賽的一等獎(jiǎng)?

          查看答案和解析>>

          (2012•峨邊縣模擬)甲題:關(guān)于x的一元二次方程x2+(2m+1)x+m2=0的實(shí)數(shù)解為x1和x2
          (1)求m的取值范圍.
          (2)當(dāng)
          x
          2
          1
          -
          x
          2
          2
          =0時(shí),求m的值.
          乙題:如圖,在△ABC中,AC=AB,以AB為直徑的半⊙O交AC于點(diǎn)E交BC于點(diǎn)D,連AD、BE.
          (1)求證:△BEC∽△ADC;
          (2)BC2=2AB•CE.

          查看答案和解析>>

          某校舉辦八年級(jí)數(shù)學(xué)素養(yǎng)大賽,比賽共設(shè)四個(gè)項(xiàng)目:七巧板拼圖、趣題巧解、數(shù)學(xué)應(yīng)用、魔方復(fù)原,每個(gè)項(xiàng)目得分都按一定百分比折算后計(jì)入總分。下表為甲、乙、丙三位同學(xué)的得分情況(單位:分)

           
          七巧板拼圖
          趣題巧解
          數(shù)學(xué)應(yīng)用
          魔方復(fù)原

          66
          89
          86
          68

          66
          60
          80
          68

          66
          80[來(lái)源:學(xué),科,網(wǎng)]
          90
          68
          (1)比賽后,甲猜測(cè)七巧板拼圖、趣題巧解、數(shù)學(xué)應(yīng)用、魔方復(fù)原這四項(xiàng)得分分別按10%,40%,20%,30%折算計(jì)入總分,根據(jù)猜測(cè),求出甲的總分;
          (2)本次大賽組委會(huì)最后決定,總分為80分以上(包括80分)的學(xué)生獲一等獎(jiǎng),F(xiàn)獲悉乙、丙的總分分別是70分,80分,甲的七巧板拼圖、魔方復(fù)原兩項(xiàng)得分折算后的分?jǐn)?shù)和是20分,問(wèn):甲能否獲得這次比賽的一等獎(jiǎng)?

          查看答案和解析>>

          某校舉辦八年級(jí)數(shù)學(xué)素養(yǎng)大賽,比賽共設(shè)四個(gè)項(xiàng)目:七巧板拼圖、趣題巧解、數(shù)學(xué)應(yīng)用、魔方復(fù)原,每個(gè)項(xiàng)目得分都按一定百分比折算后計(jì)入總分。下表為甲、乙、丙三位同學(xué)的得分情況(單位:分)

           

          七巧板拼圖

          趣題巧解

          數(shù)學(xué)應(yīng)用

          魔方復(fù)原

          66

          89

          86

          68

          66

          60

          80

          68

          66

          80

          90

          68

          (1)比賽后,甲猜測(cè)七巧板拼圖、趣題巧解、數(shù)學(xué)應(yīng)用、魔方復(fù)原這四項(xiàng)得分分別按10%,40%,20%,30%折算計(jì)入總分,根據(jù)猜測(cè),求出甲的總分;

          (2)本次大賽組委會(huì)最后決定,總分為80分以上(包括80分)的學(xué)生獲一等獎(jiǎng)。現(xiàn)獲悉乙、丙的總分分別是70分,80分,甲的七巧板拼圖、魔方復(fù)原兩項(xiàng)得分折算后的分?jǐn)?shù)和是20分,問(wèn):甲能否獲得這次比賽的一等獎(jiǎng)?

           

          查看答案和解析>>


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