}Ŀб(𰸺ͽ)
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(һ)ȡ
(1)ҳüӟȻ@w͚}wĻȡ(yng)ĻW(xu)ʽ________________________________________________
(2)߀__________(һNԇ)еμӝⰱˮķȡ
()̽
ԓСMɆTO(sh)Ӌ̽߀ԭԼa(chn)bÈD(Aּβ̎bδ)£
(1)ԓbO(sh)Ӌһȱ_Y(ji)Ĝ(zhn)_㌦ԓbõĸM(jn)ʩ__________________________________
(2)øM(jn)bM(jn)Ќ^쵽CuO׃?yu)tɫ|(zh)oˮCuSO4׃{(ln)ͬrһNoȾĚwՈNH3cCuO(yng)ĻW(xu)ʽ_________________________
()}ӑՓ
(1)ͬW(xu)J(rn)飺NH3cCuO(yng)ɵļtɫ|(zh)пܺCu2O֪Cu2OǼtɫĩһNAҺУCu+l(f)߀ԭ(yng)Cu2+CuՈO(sh)ӋһεČzԓtɫ|(zh)ǷCu2O_____________________________
(2)ڽQˆ}(1)ͬW(xu)Cu2OcCuOğ᷀(wn)Ă(qing)M(jn)ȡ
ijW(xu)оԌW(xu)(x)СMͬW(xu)ڌW(xu)(x)˰|(zh)ӑՓ\ȵ˼룬Ȼ߀ԭܷH2ǘ߀ԭCuOأO(sh)ӋȡⲢ̽}ՈㅢcԓСMĻӲо
һȡ
1ҳüӟȻ@w͚}wĻȡ(yng)ĻW(xu)ʽ ??
2߀ ?? һNԇеμӝⰱˮķȡ
̽
ԓСMɆTO(sh)Ӌ̽߀ԭԼa(chn)bãAּβ̎bδD£
1ԓbO(sh)Ӌһȱ_Y(ji)Ĝ(zhn)_㌦ԓbõĸM(jn)ʩ ??
2øM(jn)bM(jn)Ќ^쵽CuO׃?yu)tɫ|(zh)oˮCuSO4׃{(ln)ͬrһNoȾĚwՈNH3cCuO(yng)ĻW(xu)ʽ ??
}ӑՓ
1ͬW(xu)J(rn)飺NH3cCuO(yng)ɵļtɫ|(zh)пܺCu2O֪Cu2OǼtɫĩһNAҺCu+l(f)߀ԭ(yng)Cu2+CuՈO(sh)ӋһεČzԓtɫ|(zh)ǷCu2O ??
2ڽQˆ}1ͬW(xu)Cu2OcCuOğ᷀(wn)Ă(qing)M(jn)ȡ98 g Cu(OH)2wӟᵽ80~100rõɫwδ^m(x)ӟᵽ1000ɫδȫ׃ɼtɫδAsQA|(zh)72 g(j)˿ƵA ?? ɴ˵õĽY(ji)Փ ??
15֣ijW(xu)оԌW(xu)(x)СMͬW(xu)ڌW(xu)(x)˰|(zh)ӑՓ\ȵ˼Ȼ߀ԭܷH2ǘ߀ԭCuOأO(sh)ӋȡⲢ̽}ՈㅢcԓСMĻӲо
һȡ
1ȡĻW(xu)ʽ
2ڌ߀ÝⰱˮcһNԇȡ⣻
3ͬW(xu)ģʳ}ˮռȚķȻ@ҺķռJ(rn)ܷ_(d)Ŀܡ
ԓСMijͬW(xu)O(sh)ӋDʾČbãAּβ̎bδ̽߀ԭԣ
1ԓbO(sh)Ӌһȱ鱣CY(ji)Ĝ(zhn)_ԣԓbõĸM(jn)ʩ
2øM(jn)bM(jn)Ќ^쵽CuO׃?yu)tɫ|(zh)oˮCuSO4׃{(ln)ɫͬrһNoȾĚwcCuO(yng)ĻW(xu)ʽ
}ӑՓ
1ͬW(xu)J(rn)飺NH3cCuO(yng)ɵļtɫ|(zh)пܺCu2O֪Cu2OһNAҺCu+ķ(wn)ԱCu2+Cu+Cu+Cu2+ՈO(sh)ӋһεČzԓtɫ|(zh)ǷCu2O
2ڽQˆ}1ͬW(xu)Cu2OcCuOğ᷀(wn)Ă(qing)M(jn)ȡ98 gCu(OH)2wӟ80~100rõɫwĩ^m(x)ӟᵽ1000ɫĩȫ׃?yu)tɫĩAsQA|(zh)72g(j)˿ƵAĻW(xu)ʽ ɴõĽY(ji)Փ
15֣ijW(xu)оԌW(xu)(x)СMͬW(xu)ڌW(xu)(x)˰|(zh)ӑՓ\ȵ˼Ȼ߀ԭܷH2ǘ߀ԭCuOأO(sh)ӋȡⲢ̽}ՈㅢcԓСMĻӲо
һȡ
1ȡĻW(xu)ʽ
2ڌ߀ÝⰱˮcһNԇȡ
3ͬW(xu)ģʳ}ˮռȚķȻ@Һķռ⡣J(rn)ܷ_(d)Ŀܡ
ԓСMijͬW(xu)O(sh)ӋDʾČbãAּβ̎bδ̽߀ԭԣ
1ԓbO(sh)Ӌһȱ鱣CY(ji)Ĝ(zhn)_ԣԓbõĸM(jn)ʩ
2øM(jn)bM(jn)Ќ^쵽CuO׃?yu)tɫ|(zh)oˮCuSO4׃{(ln)ɫͬrһNoȾĚwcCuO(yng)ĻW(xu)ʽ
}ӑՓ
1ͬW(xu)J(rn)飺NH3cCuO(yng)ɵļtɫ|(zh)пܺCu2O֪Cu2Oһ
NAҺУCu+ķ(wn)ԱCu2+Cu+Cu+Cu2+ՈO(sh)ӋһεČzԓtɫ|(zh)ǷCu2O
2ڽQˆ}1ͬW(xu)Cu2OcCuOğ᷀(wn)Ă(qing)M(jn)ȡ98 gCu(OH)2wӟ80~100rõɫwĩ^m(x)ӟᵽ1000ɫĩȫ׃?yu)tɫĩAsQA|(zh)72g(j)˿ƵAĻW(xu)ʽ ɴõĽY(ji)Փ
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198֣ 1 B D 2 ֣
2һ NO3Al3+SO422֣ һo Fe3+Ba2+HCO32֣
3 Al3+ + 3 NH3?H2O = AlOH)3+3NH4+ 2֣
2010֣һ1)2NH4Cl
+ CaOH2 CaCl2+2NH3+2H2O 2֣
|