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        1. 21ijW(xu)dȤСMW(xu)(x)|(zh).Yϫ@˲һЩϢ:

           

          }Ŀб(𰸺ͽ)

          (12)ijW(xu)dȤСMW(xu)(x)|(zh)Yϫ@˲ĨDЩϢҶ׷QᣬˮԪԏ(qing)̼}}Ͳ}ɫoɫwQᾧwc(din)101.5档ᾧwʧȥY(ji)ˮßoˮ157A175ϰl(f)ֽ⣺

          ԓ(dng)СM҈DbÁz(yn)oˮܟĮa(chn)(b÷ϚҪӟbõ

          ȥƷx)

          (1)пհף

          x

          ԇ

          ԇ

          A

          ˿ո񲻱

          B

           

           

          C

           

           

          D

          ն̼ɔ_ęz(yn)

          (2)Дڱ(sh)(yn)?((sh)(yn)^쵽ĬF(xin))                                   

          (3)(sh)(yn)Б(yng)עİȫ}У                                                   (ٴc(din))

          (4)ԓСMO(sh)Ӌ(j)Č(sh)(yn)в֮̎Ո(qng)f׵ԭM(jn)Ľh

          ԭ                                   

          h                                   

          鿴𰸺ͽ>>

          Ҷ(H2C2O4)׷QһNҪĻԭY˽⵽P(gun)Ϣ

          Ҷˮӟ100_ʼA125r(sh)ѸA157r(sh)A_ʼֽҶܟֽˮ̼һNҊ߀ԭԚw

          Ҷ}}Ҷ}鲻ˮİɫwijW(xu)оԌW(xu)(x)СM̽IJ|(zh)M(jn)Œ(sh)(yn)

          1^ͬȵIJČ(do)(sh)(yn)100 mL 0.1mol/LIJҺ^õIJxͲ_____ ____

          2W(xu)dȤСMͬW(xu)Ì(sh)(yn)CҶᾧwܟֽɵĚwɷˆDṩbãxԇЌ(sh)(yn)ABCCCDEBbz(yn)ҶᾧwܟֽɵĚwɷՈ(qng)㰴bÏҵ±еĿո

          Ո(qng)ҶܟֽĻW(xu)ʽ _______

          (sh)(yn)fҶֽ߀ԭԚwČ(sh)(yn)F(xin)____

          z(yn)Ҷ^(qing)߀ԭͨxõԇ____

           

          鿴𰸺ͽ>>

          Ҷ(H2C2O4)׷QᣬһNҪĻԭYϣ˽⵽P(gun)Ϣ
          Ҷˮӟ100_ʼA125r(sh)ѸA157r(sh)A_ʼֽҶܟֽˮ̼һNҊ߀ԭԚw
          Ҷ}}Ҷ}鲻ˮİɫwijW(xu)оԌW(xu)(x)СM̽IJ|(zh)M(jn)Œ(sh)(yn)
          1^ͬȵIJČ(do)ԣ(sh)(yn)100 mL 0.1mol/LIJҺ^õIJxͲ_____ ____
          2W(xu)dȤСMͬW(xu)Ì(sh)(yn)CҶᾧwܟֽɵĚwɷ֡ˆDṩbxԇЌ(sh)(yn)ABCCCDEBbz(yn)ҶᾧwܟֽɵĚwɷՈ(qng)㰴bÏҵ±еĿո


          Ո(qng)ҶܟֽĻW(xu)ʽ _______
          (sh)(yn)fҶֽ߀ԭԚwČ(sh)(yn)F(xin)____
          ۙz(yn)Ҷ^(qing)߀ԭͨxõԇ____

          鿴𰸺ͽ>>

          ijW(xu)dȤСMW(xu)(x)|(zh)󣬲Yϫ@˲һЩϢ

          ()ᾧw(H2C2O42H2O)ӟ100.1 r(sh)ʧȥY(ji)ˮɞoˮ᣻

          ()oˮs157 A175 ϰl(f)ֽ⣺

          HOOCCOOHCO2+CO+H2O

          ()H2C2O4Ժ͉A(yng)(yng)}H2C2O4+Ba(OH)2*BaC2O4+2H2O

          ԓСMˆDʾČ(sh)(yn)bãͨ^(sh)(yn)(yn)CoˮܟֽĮa(chn)÷(yng)a(chn)ļCOw߀ԭFijN(FezOy)Դ_FexOyĽM

          Ո(qng)شІ}

          (1)(sh)(yn)ăxψDʾxB?yn)飺e_________________________________________

          (2)ԓMͬW(xu)M(jn)Ќ(sh)(yn)Ⱥ?yn)________________

          c(din)ȼB̎(c)ľƾ

          ڙz(yn)(sh)(yn)bõĚԣ

          ۷(yng)Y(ji)Ϩƾ

          c(din)ȼC̎ľƾ_ʼ(yng)(du)bBd̎wM(jn)(yn)c(din)ȼd̎ľƾ

          ?q)?yn)bbˎƷ

          (3)Dbгʯˮ________________________________

          Bbгʯˮ________________________________________________

          (4)Bbd̎ƾ________________________________

          (5)֪Ӳ|(zh)ܵ|(zh)45.00 g(yng)ǰ14.80 g FexOyƷ(yng)Ӳ|(zh)cʣwĿ|(zh)53.40 gӋ(j)ƷFexOyxy=________________

          (6)ԓСMO(sh)Ӌ(j)Č(sh)(yn)________________(С򡰟o)֮̎вՈ(qng)f׵ԭ________________

          鿴𰸺ͽ>>

          һx}}2lС}ÿС}242

          1D       2C       3C       4D       5C       6C       7D       8D       9C      l0C

          l1B      12C     13C     14C     15D     16C     l 7B     l 8D     19B     20A

          }1С}12֡

          2112֣

          1Bboˮ~z(yn)ˮ⣻Cbʯˮz(yn)̼ÿ1֣

          2(yn)c(din)ȼE̎Ěw{(ln)ɫ2(yn)1֣

                3c(din)ȼǰ(yng)(yn)COж(sh)(yn)ҪͨL(fng)ӟr(sh)Ҫܟ2֣

                4]l(f)IJcʯˮ(yng)˲}(hu)ɔ_CO2ęz(yn)2֣

                     bBCbgһ(g)bˮAҺϴbã2֣

          }3С}38

          22ÿ212֣

          1H30

          2>

          3A1+3NH3?H2O=AlOH3 +3NH

          4NH4AlSO42

          5336

          23ÿ2֣l 2֣

          1ASi          BMg

          2ȻVˮ

          3Si+2NaOH+H2O=Na2SiO3+2H2

                       Mg2Si+4HCl=SiH4+2MgCl2

                       SiO2+Na2CO3 Na2SiO3+CO2

          24ÿ214֣

          12C4 H10+13O2=8CO2+l0H2O

          2O2+2CO2+4e =2CO

              3CO2    ؓ(f)O(yng)a(chn)

                42Cl+2H2OC12+H2+2OH

                       5C12+I2+6H2O=10HCl+2HIO3

               560

          }lС}l0

          251Fe+H2SO4=FeSO4+H2

                     FeSO4+NH42SO4+6H2O=NH42FeSO42?6H2O2֣

          2⣺O(sh)ɣNH42FeSO42?6H2O|(zh)x molʽ֪

                     H2SO4~FeSO4~NH42FeSO42?6H2 O

                     1 mol                              l mol

                     15310 mol               x  mol

                                                 x=0045

                ɣNH42FeSO42?6H2O|(zh)飺0045 mol392 gmol=1764 g

          3 518154 H2O2֣ 

          83332֣

           

           

           


          ͬ(x)(c)