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        1. 21.肼(N2H4)是火箭發(fā)動機的燃料.反應(yīng)時N2O4為氧化劑.生成氮氣和水蒸氣.已知: N2(g)+2O2(g)=N2O4(g),△H=+8.7kJ/mol N2H4(g)+O2(g)=N2(g)+2H2O(g),△H=-534.0kJ/mol 下列表示肼跟N2O4反應(yīng)的熱化學方程式.正確的是 A.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g),△H=-542.7kJ/mol B.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g),△H=-1059.3kJ/mol C.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g),△H=-1076.7kJ/mol D.N2H4(g)+N2O4(g)=N2(g)+2H2O(g),△H=-1076.7kJ/mol 查看更多

           

          題目列表(包括答案和解析)

          肼N2H4是火箭發(fā)動機的燃料,反應(yīng)時N2O4為氧化劑,生成氮氣和水蒸氣.已知:
          N2(g)+2O2(g)=N2O4(g);△H=+8.7kJ/mol
          N2H4(g)+O2(g)=N2(g)+2H2O(g);△H=-534.0kJ/mol
          下列表示肼跟N2O4反應(yīng)的熱化學方程式,正確的是( 。

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          肼N2H4是火箭發(fā)動機的燃料,反應(yīng)時N2O4為氧化劑,生成氮氣和水蒸氣.已知:
          N2(g)+2O2(g)=N2O4(g);△H=+8.7kJ/mol
          N2H4(g)+O2(g)=N2(g)+2H2O(g);△H=-534.0kJ/mol
          下列表示肼跟N2O4反應(yīng)的熱化學方程式,正確的是( 。
          A.N2H4(g)+
          1
          2
          N2O4(g)=
          3
          2
          N2(g)+2H2O(g);△H=+538.35kJ/mol
          B.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1059.3kJ/mol
          C.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1076.7kJ/mol
          D.N2H4(g)+
          1
          2
          N2O4(g)=
          3
          2
          N2(g)+2H2O(g);△H=-1076.7kJ/mol

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          肼(N2H4)是火箭發(fā)動機的燃料,反應(yīng)時N2O4為氧化劑,生成氮氣和水蒸氣.已知:

          N2(g)+2O2(g)=N2O4(g);△H=+8.7kJ/mol

          N2H4(g)+O2(g)=N2(g)+2H2O(g);△H=-534.0kJ/mol

          下列表示肼跟N2O4反應(yīng)的熱化學方程式,正確的是

          [  ]

          A.

          2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-542.7kJ/mol

          B.

          2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1059.3kJ/mol

          C.

          2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1076.7kJ/mol

          D.

          N2H4(g)+N2O4(g)=N2(g)+2H2O(g);△H=-1076.7kJ/mol

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          肼(N2H4)是火箭發(fā)動機的燃料,反應(yīng)時N2O4為氧化劑,生成氮氣和水蒸氣。已知:

          N2(g)+2O2(g)====N2O4(g);ΔH=+8.7 kJ·mol-1

          N2H4(g)+O2(g) ====N2(g)+2H2O(g);ΔH=-534.0 kJ·mol-1

          下列表示肼跟N2O4反應(yīng)的熱化學方程式,正確的是

          A.2N2H4(g)+N2O4(g)====3N2(g)+4H2O(g);ΔH=-542.7 kJ·mol-1

          B.2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g);ΔH=-1 059.3 kJ·mol-1

          C.2N2H4(g)+N2O4(g) ====3N2(g)+4H2O(g);ΔH=-1 076.7 kJ·mol-1

          D.N2H4(g)+N2O4(g)====N2(g)+2H2O(g);ΔH=-1 076.7 kJ·mol-1

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          肼(N2H4)是火箭發(fā)動機的燃料,反應(yīng)時N2O4為氧化劑,生成氮氣和水蒸氣。已知:

          N2(g)+2O2(g)=N2O4(g);△H=+8.7kJ/mol 

          N2H4(g)+O2(g)=N2(g)+2H2O(g);△H=-534.0kJ/mol

          下列表示肼跟N2O4反應(yīng)的熱化學方程式,正確的是                                        (   )

                 A.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-542.7kJ/mol

                 B.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1059.3kJ/mol

                 C.2N2H4(g)+N2O4(g)=3N2(g)+4H2O(g);△H=-1076.7kJ/mol

                 D.N2H4(g)+N2O4(g)=N2(g)+2H2O(g);△H=-1076.7kJ/mol

           

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