Question

一條彈性繩沿x軸方向放置，繩左端點(diǎn)在原點(diǎn)O處．用手握住繩左端點(diǎn)使其沿y軸方向做周期為1.0s的簡(jiǎn)諧運(yùn)動(dòng)，于是在繩上形成一列簡(jiǎn)諧波．當(dāng)波傳到x=1.0m處的M點(diǎn)時(shí)，此時(shí)的波形如圖所示．那么再經(jīng)過(guò)______s，波傳到x=4.5m處的N點(diǎn)．當(dāng)繩的左端點(diǎn)的運(yùn)動(dòng)路程為0.88m時(shí)，N點(diǎn)的運(yùn)動(dòng)路程為_(kāi)_____cm．

Answer 1

由圖可知波長(zhǎng)λ=2m，波速v=

λ

T

=2m/s，波傳到x=4.5m處的N點(diǎn)的時(shí)間t=

x

v

=

3.5

2

s=1.75s．
由圖讀出振幅A=0.08m，當(dāng)繩的左端點(diǎn)的運(yùn)動(dòng)路程為0.88m=11A，經(jīng)過(guò)的時(shí)間為t₁=

0.88

4×0.08

T=2.75s
N點(diǎn)的運(yùn)動(dòng)時(shí)間為t₂=t₁-t=1s=

T

2

，則N點(diǎn)的運(yùn)動(dòng)路程為S=2A=16cm．
故本題答案是：1.75；16