Question

（本小題滿(mǎn)分14分）

         已知函數(shù)．

         （Ⅰ）當(dāng)時(shí)，求函數(shù)的圖象在處的切線(xiàn)方程；

         （Ⅱ）判斷函數(shù)的單調(diào)性；

         （Ⅲ）若函數(shù)在上為增函數(shù)，求的取值范圍．

 

Answer 1

【答案】

（Ⅰ）．

（Ⅱ）當(dāng)時(shí)，函數(shù)在單調(diào)遞增；

當(dāng)時(shí)，函數(shù)在單調(diào)遞減，在上單調(diào)遞增．

（Ⅲ）．

【解析】(I)當(dāng)a=2時(shí)，先求出的值，即切線(xiàn)的斜率，然后寫(xiě)出點(diǎn)斜式方程，再化成一般式即可.

(II)先求導(dǎo)，可得,然后再對(duì)和a<0兩種情況進(jìn)行討論研究其單調(diào)性.

(III)本小題轉(zhuǎn)化為在上恒成立，也可考慮求出f(x)的增區(qū)間D，然后根據(jù)求解也可.

（Ⅰ）當(dāng)時(shí)，（），········································· 1分

∴，···································································· 2分

∴ ，所以所求的切線(xiàn)的斜率為3．······················································· 3分

又∵，所以切點(diǎn)為.

 故所求的切線(xiàn)方程為：．······································································· 4分

（Ⅱ）∵，

∴······························································· 5分

①當(dāng)時(shí)，∵，∴；····························································· 6分

②當(dāng)時(shí)，

由，得；由，得；·························· 8分

綜上，當(dāng)時(shí)，函數(shù)在單調(diào)遞增；

當(dāng)時(shí)，函數(shù)在單調(diào)遞減，在上單調(diào)遞增．········ 9分

（Ⅲ）①當(dāng)時(shí)，由（Ⅱ）可知，函數(shù)在單調(diào)遞增．此時(shí)，，故在上為增函數(shù)．······································································································· 11分

②當(dāng)時(shí)，由（Ⅱ）可知，函數(shù)在上單調(diào)遞增．

∵　在上為增函數(shù)，

∴　，故，解得，

∴　．······························································································ 13分

綜上所述，的取值范圍為．                      14分