ˎƷ2% NaOHҺϡHClϡHSO
KHCO
ҺݝH
SO
CaCO
wK
CO
ĩ
xbãDʾ
Ո(j)}ĿҪІ}
Ո±ҪxbúˎƷ
(xing)(ni) | CO | sϴbãY | Ƃa(chn)ƷbãZ |
xb ̖ |
|
| C |
xˎƷ ̖ |
|
|
(2)Ιz(yn)xCOl(f)bãXĚՈҪ^̣__________
3bðXYZBӲzԺ(dng)ˎƷ(sh)(yn)r(sh)Xbаl(f)W(xu)(yng)xӷʽ_____________Ybгȥs|(zh)_________________
4£ZbõNaOHҺͨ^CO2wĿ______________
5ҪCZbвw]^Һ}NaOHҺȲܳ^________________%|(zh)?jn)?sh)
P(gun)|(zh)ڳأ25 棩r(sh)ܽ
W(xu)ʽ | Na | NaHCO | NaOH | NaCl | Na |
ܽ g/100 g H | 21.3 | 9.60 | 107 | 35.8 | 19.4
|
(1)f ڢ b
(2)1oοP(gun)]ڟмһˮʹ¶˹ܿڽ]ˮУ܃(ni)Һһ߶ȲfbõĚ÷2oοP(gun)]ڟмһˮʹ¶˹ܿڽ]ˮУסܿ̎F(xin)ֺ¶˹ܿ̎F(xin)һˮfbõĚão֣
3CaCO+2H
==Ca
+CO
+H
O HCl
(4)ʹҺеNaOHȫD(zhun)NaHCO
(5)4?37
Ҫ_(d)(sh)(yn)?zi)?yng)ԓS_SáSP(gun)Sͣհl(f)ԭbfȡCOwȻͨ^ʢKHCO
ҺbbԳȥCO
леHClԭ:KHCO
+HCl==KCl+CO
+H
OٌCO
ͨϡNaOHҺмɣԭǣCO
+NaOH==NaHCO
NaOHҺָͨ^CO
õõNaHCO
ҺO(sh)NaHCO
Һк100 gˮtṩ(sh)(j)֪˕r(sh)ҺNaHCO
|(zh)9.60 g(j)(yng)CO
+NaOH==NaHCO
NaOH|(zh)飺
=4.57 gNaOHҺw(NaOH)=
100%=4.37%
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