日韩亚洲一区中文字幕,日韩欧美三级中文字幕在线,国产伦精品一区二区三区,免费在线欧美性爱链接

      1. <sub id="o5kww"></sub>
        <legend id="o5kww"></legend>
        <style id="o5kww"><abbr id="o5kww"></abbr></style>

        <strong id="o5kww"><u id="o5kww"></u></strong>
        1. ijW(xu)СMͬW(xu)MP(gun)NO2wϵЌ

          1ψDʾƿз~Ƭ_Һ©  

          ^ƿЮa(chn)wɫ        ԇռĚwɫ      ûW(xu)ʽʾԭ                          

          2ƿˮƿ(ni)wɫ      ׃׃׃\ʹûW(xu)ZͱҪfɫ׃ԭ                                  

          380r0.40 mol N2O4w2 Lѽ(jng)յĹ̶ݷe]аl(f)(yng)һΕrgԓ(ni)|(zh)Mзõ”(sh)(j)

          rgs

          0

          20

          40

          60

          80

          100

          n(N2O4)/mol

          0.40

          a

          0.20

          c

          d

          e

          n(NO2)/mol

          0.00

          0.24

          b

          0.52

          0.60

          0.60

          Ӌa =       ˜ضȕrԓ(yng)ƽⳣ(sh)K=        

          ƽԓٳ0.2molN2O4wtN2O4D(zhun)         pС׃

          ۸׃lʹ(yng)_ƽʹc(NO2)/c(N2O4)ֵ׃СĴʩУ̖      

          AN2O4ʼ           Bߜض

          CʹøЧ߻                DϚwͨϡКw

           

          𰸡

          11֣

          1tɫ 1֣ oɫ 1֣

          Cu + 4HNO3 ()==== Cu(NO3)2 + 2NO2 + 2H2O  1֣

          3NO2 + H2O ==== 2HNO3 + NO 1֣

          2׃\ 1֣  2NO2  N2O4  H<0 ضȽͣƽ(yng)Ƅc(NO2)Ƚ 2֣

          3  a=0.28 1֣     1.8 1֣      ڜpС1֣  A 1֣

           

          (x)ϵд
          P(gun)(x)}

          ĿлW(xu) Դ

          IF~Cu2OǼtɫĩϣ֪~ϡCuCuSO4ijW(xu)СM̽Fe2O3Cu2OMɵĻЃ|(zh)СijͬW(xu)JֻҪȡĩϡͨ^^F(xin)󼴿ɣ
          1^аl(f)ķ(yng)Уxӷʽʾ
          Fe2O3+6H+=2Fe3++3H2O  
          Cu2O+2H+=Cu+Cu2++H2O
          Cu2O+2H+=Cu+Cu2++H2O
            
          Cu+2Fe3+=2Fe2++Cu2+
          Cu+2Fe3+=2Fe2++Cu2+

          2^쵽Һ׃?yu){ɫйwʣtnCu2O
          nFe2O3 =
           IIքe]ăɂ(yng)M·(yng)
          󷴑(yng)ңAg+2Bg
           2Cg    
          ҷ(yng)ң2Zg
          Xg+Yg
          ڷ(yng)֮gПoĦɻӵܷ࣮(yng)_ʼ_ƽrP(gun)׃Dʾ

          1Ag+2Bg      2Cg  ġH
           0=
          2ƽ⣨Iƽ⣨Xwe֔(sh)
          b
          b
          ̖
          aһ    bһ    c
          3_ƽ⣨IrAD(zhun)ʞ
          5
          11
          5
          11

          鿴𰸺ͽ>>

          ĿлW(xu) Դ

          ֪ȻcƷкNa2SO4 Na2CO3ijW(xu)СMͬW(xu)ӋMἃ򞣮
          Ӣҽ̾W(wng)
          (j)̻شІ}
          1ԇĻW(xu)ʽCQ
          ԇA
           
          ԇD
           
          C
           

          2ԇAԇNa2CO3Ⱥܷ{(dio)Q
           
          ʲô
           

          3ԇD
           
          ДԇD_mҪ(j)
           

          4вE(yng)ĻW(xu)ʽ
          ڢ۲
           
          
          ڢݲ
           

          鿴𰸺ͽ>>

          ĿлW(xu) Դ

          ijW(xu)СMͬW(xu)MP(gun)NO2wϵЌ

          1ψDʾƿз~Ƭ_Һ©  

          ^ᣬƿЮa(chn)wɫ        ԇռĚwɫ      ûW(xu)ʽʾԭ                          

          2ƿˮƿ(ni)wɫ     ׃׃׃\ʹûW(xu)ZͱҪfɫ׃ԭ                                 

          380r0.40 mol N2O4w2 Lѽ(jng)յĹ̶ݷe]аl(f)(yng)һΕrgԓ(ni)|(zh)Mзõ”(sh)(j)

          rgs

          0

          20

          40

          60

          80

          100

          n(N2O4)/mol

          0.40

          a

          0.20

          c

          d

          e

          n(NO2)/mol

          0.00

          0.24

          b

          0.52

          0.60

          0.60

          Ӌa =       ˜ضȕrԓ(yng)ƽⳣ(sh)K=        

          ƽԓٳ0.2molN2O4wtN2O4D(zhun)         pС׃

          ۸׃lʹ(yng)_ƽʹc(NO2)/c(N2O4)ֵ׃СĴʩУ̖     

          AN2O4ʼ          Bߜض

          CʹøЧ߻               DϚwͨϡКw

           

          鿴𰸺ͽ>>

          ĿлW(xu) Դ2012úʡľ˹һиόW(xu)ڵĴ{(dio)пԇW(xu)ԇ }

          ijW(xu)СMͬW(xu)MP(gun)NO2wϵЌ

          1ψDʾƿз~Ƭ_Һ©^ƿЮa(chn)wɫ       ԇռĚwɫ     ûW(xu)ʽʾԭ                          
          2ƿˮƿ(ni)wɫ     ׃׃׃\ʹûW(xu)ZͱҪfɫ׃ԭ                                 
          380r0.40 mol N2O4w2 Lѽ(jng)յĹ̶ݷe]аl(f)(yng)һΕrgԓ(ni)|(zh)Mзõ”(sh)(j)

          rgs
          0
          20
          40
          60
          80
          100
          n(N2O4)/mol
          0.40
          a
          0.20
          c
          d
          e
          n(NO2)/mol
          0.00
          0.24
          b
          0.52
          0.60
          0.60
          Ӌa =       ˜ضȕrԓ(yng)ƽⳣ(sh)K=        
          ƽԓٳ0.2molN2O4wtN2O4D(zhun)        pС׃
          ۸׃lʹ(yng)_ƽʹc(NO2)/c(N2O4)ֵ׃СĴʩУ̖     
          AN2O4ʼ           Bߜض
          CʹøЧ߻                DϚwͨϡКw

          鿴𰸺ͽ>>

          ͬ(x)Դ