Question

計(jì)算：

x-3

x2-1

÷

x2+x

x2+2x+1

-

1

x-1

．

Answer 1

分析：本題需先根據(jù)分式的混合運(yùn)算順序和法則分別進(jìn)行計(jì)算，即可求出答案．

解答：解：

x-3

x2-1

÷

x2+x

x2+2x+1

-

1

x-1

=

x-3

(x+1)(x-1)

×

(x+1)2

x(x+1)

-

1

x-1

=

x-3

x(x-1)

-

1

x-1

=-

3

x(x-1)

．

點(diǎn)評(píng)：本題主要考查了實(shí)數(shù)的運(yùn)算，在解題時(shí)要根據(jù)實(shí)數(shù)運(yùn)算的法則和順序分別進(jìn)行計(jì)算是本題的關(guān)鍵．